9X^2-3x-598=0

Solution for 9X^2-3x-598=0 equation:

9X^2-3X-598=0

a = 9; b = -3; c = -598;
Δ = b2-4ac
Δ = -32-4·9·(-598)
Δ = 21537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21537}=\sqrt{9*2393}=\sqrt{9}*\sqrt{2393}=3\sqrt{2393}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{2393}}{2*9}=\frac{3-3\sqrt{2393}}{18}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{2393}}{2*9}=\frac{3+3\sqrt{2393}}{18}
$